2a^2=2304

Solution for 2a^2=2304 equation:

2a^2=2304

We move all terms to the left:

2a^2-(2304)=0

a = 2; b = 0; c = -2304;
Δ = b2-4ac
Δ = 02-4·2·(-2304)
Δ = 18432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18432}=\sqrt{9216*2}=\sqrt{9216}*\sqrt{2}=96\sqrt{2}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96\sqrt{2}}{2*2}=\frac{0-96\sqrt{2}}{4}
=-\frac{96\sqrt{2}}{4}
=-24\sqrt{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96\sqrt{2}}{2*2}=\frac{0+96\sqrt{2}}{4}
=\frac{96\sqrt{2}}{4}
=24\sqrt{2}
$